ISITEKS: DARI SIKLUS K MENJADI HUKUM GABUNGAN AVOGADRO, BOYLE, GAY-LUSSAC, CHARLES, ARCHIMEDES

Ditulis oleh: Dika Sistrandari & Djaka Sasmita
DARI:

${\color{DarkOrange} T\equiv pf\left ( \bar{V} \right )\leftrightarrow \bar{V}=g\left (\frac{T}{p} \right )}$

${\color{DarkOrange} \bar{V}\equiv \frac{V}{n}}$ ${\color{DarkOrange} \frac{p}{T}dV=dif eksak}$

JADIKAN :
${\color{DarkOrange} \frac{pV}{nT}=konstan}$

JAWAB:

untuk contoh ${\color{DarkOrange} N_{2}O_{4}(g)\rightleftharpoons 2NO_{2}(g)}$

${\color{DarkOrange} 0=\oint \frac{p}{T}dV=\int_{1molN_{2}O_{4}}^{2molNO_{2}}\frac{p_{1}}{T_{1}}\bar{V_{1}}dn+0_{isovolum}+\int_{2molNO_{2}}^{1molN_{2}O_{4}}\frac{p_{2}}{T_{2}}\bar{V_{2}}dn+0_{isovolum}}$

${\color{DarkOrange} 0=\left [ \frac{p_{1}\bar{V_{1}}}{T_{1}} \right ]_{N_{2}O_{4}}\left ( 2-1 \right )+\left [ \frac{p_{2}\bar{V}_{2}}{T_{2}} \right ]_{NO_{2}}(1-2)}$

${\color{DarkOrange} \left [ \frac{p_{1}\bar{V_{1}}}{T_{1}} \right ]_{N_{2}O_{4}}=\left [ \frac{p_{2}\bar{V_{2}}}{T_{2}} \right ]_{NO_{2}}\rightarrow \frac{p\bar{V}}{T}=konstan}$

${\color{DarkOrange} =R}$

${\color{DarkOrange} \frac{pV}{nT}=R}$ = HUKUM GABUNGAN AVOGADRO, BOYLE, GAY-LUSSAC, CHARLES, ARCHIMEDES.

ISITEKS

Kamis, 22 Oktober 2015

DARI SIKLUS K MENJADI HUKUM GABUNGAN AVOGADRO, BOYLE, GAY-LUSSAC, CHARLES, ARCHIMEDES

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